doubang9906 2013-07-25 21:28
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获取mysql查询返回的每个元素的计数

This is my query:

SELECT `Brand`,`Colour`,`Occassion`,`Fabric`,`Type` 
FROM `deals` 
WHERE `Size` 
LIKE '%XS%';

It returns 35 results. Now, what i want is a count of each of the columns (Brand, colour etc) which are present in the above resultset to create a histogram. I am not sure about how to do this.

Any help is appreciated.

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  • dongzao3923 2013-07-25 21:46
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    I think ideal result should look like this:

    $data = array(
        "Brand" => array(brand1 => 1, brand2 => 2),
        "Colour" => array(colour1 => 1, colour2 => 2),
        "Occassion" => array(Occassion1 => 1, Occassion2 => 2),
    );
    

    For each subarray we can draw a histogram. The code will look like this:

    $query = "
    SELECT
        `Brand`,`Colour`,`Occassion`,`Fabric`,`Type` 
    FROM 
        `deals` 
    WHERE
        `Size` LIKE '%XS%'";
    
    $data = array(
        "Brand" => array(),
        "Colour" => array(),
        "Occassion" => array(),
        "Fabric" => array(),
        "Type" => array(),
        );
    
    if ($result = $mysqli->query($query)) {
    
        /* fetch associative array */
        while ($row = $result->fetch_assoc()) {
            foreach($row as $key => $value)
            {
                $data[$key][$value]++;
            }
        }
    
        /* free result set */
        $result->free();
    }
    

    Or we can define $data subarrays inside foreach to make the program more flexible:

    $data = array();
    ...
        foreach($row as $key => $value)
        {
            if(!isset($data[$key]))
            {
                $data[$key] = array();
            }
            $data[$key][$value]++;
        }
    ...
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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