将shell变量作为参数传递给PHP脚本

Question

I want to pass shell variables to a PHP script. This is my attempt:

var1=`echo name_16`
var2=`echo /home/place/end/name_16`
php script.php ${var1} ${var2}

These variables contain special characters [)(*&^%$#@!~<>_] but no hyphens.

I am running PHP 4.3.9 cgi.

I attempt to pick up the variables in my PHP script thus:

    $fish = $argv[1];
    $sticks = $argv[2];

These variables come up as null. I've tried var_dump($argv); and this returns null as well.
Am I passing these parameters correctly or am I missing something here?

Answer 1

I wanted to add this as a comment, but need the formatting ability of an answer to respond.

There's something else wrong with the code. A basic test of arguments shows that the variables should work.

Contents of foo.php:

<?php
    print "$argv[1]
$argv[2]
" ;

    $x = $argv[1];
    $y = $argv[2];

    print "$x
$y
";
?>

Then the setup:

$ var1=`echo name_16`
$ var2=`echo /home/place/end/name_16`

And execution:

$ php foo.php ${var1} ${var2}
name_16
/home/place/end/name_16
name_16
/home/place/end/name_16
$

So the problem is not reproducible using the information provided. The above is run with PHP 5.2.6 (cli) (built: May 8 2008 08:53:44), so it is, perhaps, a difference in version behavior.