Php使用数组显示图片

Question

I'm trying to show images from some directory using foreach.. But the problem is it's showing results in array, so if i want to print out first image I have to use $imag['0']..

Is there any way that I can bypass this number in this brackets?

Here's my code...

<?php
$domena = $_SERVER['HTTP_HOST'];
$galerija = $_POST['naziv'];
$galerija = mysql_real_escape_string($galerija);

define('IMAGEPATH', 'galleries/'.$galerija.'/');

foreach(glob(IMAGEPATH.'*') as $filename){
    $imag[] =  basename($filename);
?>
<img src="http://<?php echo $domena; ?>/galerija/galleries/<?php echo $galerija; ?>/<?php echo $imag['0']; ?>">

Answer 1

Well you could first not create the array in the foreach statement and instead just print the img:

echo '<img src="', $domena ,'/galerija/galleries/', $galerija ,'/', $filename,'">';

Or you could iterate the array.

foreach($imag as $img): ?>
    <img src="http://<?php echo $domena; ?>/galerija/galleries/<?php echo $galerija; ?>/<?php echo $img ?>">
<?php endforeach; ?>