I'm creating a messaging system for my site and i'm trying to display your friends and i'm having trouble as i'm getting the error:
Select Friend: Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT `user_two` FROM `friends` WHERE (`user_one`='2')' at line 1
Heres My PHP Code:
mysql_connect("************", "*****", "**********");
mysql_select_db("******");
if(isset($_GET['user']) && !empty($_GET['user'])){
echo "Send Message To " . getuser($_GET['user'], 'first_name');
} else {
echo "Select Friend: ";
$my_id = $_SESSION['user_id'];
$friend_list = mysql_query("SELECT `user_one` FROM `friends` WHERE (`user_two`='$my_id') OR SELECT `user_two` FROM `friends` WHERE (`user_one`='$my_id')");
if (!$friend_list) { // add this check.
die('Invalid query: ' . mysql_error());
}
while($run_user = mysql_fetch_array($friend_list)){
if($run_user['user_one'] == $my_id){
echo "1";
} else {
echo "2";
}
}
}
And heres my friends table structure:
`id` int(11) AUTO INCREMENT PRIMARY
`user_one` int(11)
`user_two` int(11)
I'm trying to get the friends ID and make sure it isn't mine and then display the information i need to, i am a little bit rusty with SQL so just have that in mind.
