dougaoxian8922 2012-11-14 14:39
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检查会话 - php不打印[关闭]

<?php session_start();
$_SESSION['loggedIn'] = "no";
echo "Logged In: ". $_SESSION['loggedIn'];

if($_SESSION['loggedIn']=="yes"): 
    echo "logged in";
}
else{
    echo "not logged in";
}
?>

I am simply trying to check if the session "loggedIn" is yes or no, but the program doesn't print anything.

Why does it not print anything?

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4条回答 默认 最新

  • dsvd407787736 2012-11-14 14:41
    关注

    You are using alternative if/then as well as regular syntax.

    if($_SESSION['loggedIn']=="yes"):
    

    should be

    if($_SESSION['loggedIn']=="yes"){
        echo "logged in";
    }
    else{
        echo "not logged in";
    }
    

    its a simple syntax error

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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