请问一下这个绝对素数的代码编译错误是由于什么原因?

Question

#include
#include
int prime(unsigned int);
unsigned int rev(unsigned int);
int main()
{
unsigned int n,m;
scanf("%u",&n);
if(prime(n)!=0)
m=rev(n);
else
{
printf("no\n");
return 0;
}
{
if(prime(m)!=0)
printf("yes\n");
else
printf("no\n");
return 0;
}
int prime(unsigned int x)
{
int i,k;
k=sqrt(x);
for(i=2;i<=k;i++)
{
if(x%i==0)
return 0;
else if(i>k)
return 1;
}
}
unsigned int rev(unsigned int y)
{
unsigned int z=0;
while(y!=0)
{
z=z*10+y%10;
y=y/10;
}
return z;
}
}

Answer 1

#include<stdio.h> 
#include<math.h>
int prime(unsigned int);
unsigned int rev(unsigned int);
int main()
{
    unsigned int n,m;
    scanf("%u",&n);
    if(prime(n)!=0)
        m=rev(n);
    else
    {
        printf("no\n");
        return 0;
    }
    if(prime(m)!=0)
        printf("yes\n");
    else
        printf("no\n");
    return 0;
}
int prime(unsigned int x)
{
    int i,k;
    k=sqrt((double)x); 
    for(i=2;i<=k;i++)
    {
        if(x%i==0)
            return 0;
    }
    return 1;
}

unsigned int rev(unsigned int y)
{
    unsigned int z=0;
    while(y!=0)
    {
        z=z*10+y%10;
        y=y/10;
    }
    return z;
}

以后提问把原始题目也贴出来

还有，代码要缩进正确，才好阅读。这次帮你都调整了，下次自己要注意