如何通过在PHP中给出日期来识别偶数或星期六

Question

I want to calculate total number of working days in between two date. Here we include second and fourth Saturday as working day(i.e all Even Saturdays are considered as Holiday) I can get the day of the particular date by using below code

$day = ‘2015-11-07’;
$dayName = date("l",strtotime($day));

if ($dayName =='saturday') {
    ...
}

then I have to find whether that particular date falls under first Saturday of November or second Saturday. Is there any option in doing that?

I have the code to calculate total number of days excluding all Saturdays,Sunday and holidays. I got that code from another question

But I want to identify even saturdays and I will detect that saturdays in total days.

Answer 1

Get all days between the two end-points, then apply your logic to each, accumulating the ones that match:

function work_days_between_two_dates(\DateTime $begin, \DateTime $end) {
    $workdays = [];
    $all_days = new DatePeriod($begin, new DateInterval('P1D'), $end->modify('+1 day'));
    foreach ($all_days as $day) {
        $dow = (int)$day->format('w');
        $dom = (int)$day->format('j');
        if (1 <= $dow && $dow <= 5) { // Mon - Fri
            $workdays[] = $day;
        } else if (6 == $dow && 0 == $dom % 2) { // Even Saturday
            $workdays[] = $day;
        }
    }
    return $workdays;
}

Live example.

For November 2015 (dates between 11/1 and 12/1), this algorithm marks the following as work days:

    November 2015
Su Mo Tu We Th Fr Sa
 -  2  3  4  5  6  -
 -  9 10 11 12 13 14
 - 16 17 18 19 20 -
 - 23 24 25 26 27 28
 - 30