dqkelut8423 2010-10-26 12:06
浏览 37
已采纳

在PHP和MYSQL中创建SELECT的正确方法是什么?

How can i do a select from a variable received from a form?

I have the following code but i think that i cannot do this : '%'.$texto.'%'

$busqueda=$_POST['texto'];
$tipo=$_POST['tipo'];

if($tipo='titulo')
    $res=mysql_query("SELECT * FROM LIBRO WHERE LI_TITULO like '%'.$texto.'%'",$conexion);

What should i do? Thank you for your time.

  • 写回答

3条回答 默认 最新

  • duanlei4759 2010-10-26 12:08
    关注
    mysql_query("SELECT * FROM LIBRO WHERE LI_TITULO like '%{$busqueda}%'",$conexion); 
    

    Edit:

    You also have bug in your if statement:

    if($tipo='titulo') 
    

    That's not a comparison, it's an assignment. If you want to compare, use

    if($tipo==='titulo') 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 TLS1.2协议通信解密
  • ¥40 图书信息管理系统程序编写
  • ¥20 Qcustomplot缩小曲线形状问题
  • ¥15 企业资源规划ERP沙盘模拟
  • ¥15 树莓派控制机械臂传输命令报错,显示摄像头不存在
  • ¥15 前端echarts坐标轴问题
  • ¥15 ad5933的I2C
  • ¥15 请问RTX4060的笔记本电脑可以训练yolov5模型吗?
  • ¥15 数学建模求思路及代码
  • ¥50 silvaco GaN HEMT有栅极场板的击穿电压仿真问题