在php打印函数中编写具有参数的onclick方法

Question

I'm having problems with writing an onclick method in php print in code below:

    <?php print "<p><small> <a  href='#' onclick='ajaxMenu('comments.php?news=".$fileContent['id']."');>".$number. " ".$text." </small> </a> </p>"; ?>

Given code doesn't work. I believe it's because of combination of single and double quotes in it. Can anyone help me to solve this?

Answer 1

You can escape " characters by having a forward slash \"

<?php echo( "<a href=\"#\" onclick=\"onMenu('this is the menu');\">This is a link</a>" ); ?>