如何在PHP中组合两个IF语句

Question

Okay i know this is a newb question, but how would i go about only performing IF 2 if IF 1 (text: test appears in data string.) I've tried combining the two but end up with all sorts of issues. So if test doesnt show up the loops skipped, if it does then the regex code i have in IF 2 will be ran.

$data = 'hello world "this is a test" last test';


// IF 1 
if (stripos($data, 'test') !== false) {
}


// IF 2
if (preg_match('/"[^"]*"/i', $data, $regs)) {
$quote = str_word_count($regs[0], 1);
$data = str_replace($regs[0], '"'.implode(' ', $quote).'"', $data);
}

echo $data;

Answer 1

Either:

if (stripos($data, 'test') !== false) {
    if (preg_match('/"[^"]*"/i', $data, $regs)) {
        $quote = str_word_count($regs[0], 1);
        $data = str_replace($regs[0], '"'.implode(' ', $quote).'"', $data);
    }
}

Or:

if (stripos($data, 'test') !== false && preg_match('/"[^"]*"/i', $data, $regs)) {
    $quote = str_word_count($regs[0], 1);
    $data = str_replace($regs[0], '"'.implode(' ', $quote).'"', $data);
}

Both do the same thing. The && operator means "and". The || operator means "or".