dq13733519262 2012-12-07 20:46 采纳率: 0%
浏览 13
已采纳

我在Wordpress中需要什么功能来解析自定义分类的子类别的URL?

I looked around and noticed many questions about this were asked already. But none had an answer I needed.

Below you find an php/html script of a page template in my own theme (I use them because of more functionality on corporate websites). That's NOT the problem. Works like a charm.

What does this script do?

It outputs all categories their featured image (via plugin 'Categories Images') under the taxonomy clients.

Works perfect!! That's not the problem.

The only LINE of code I need is mentioned in the PHP loop as a comment... Could anyone please help me?

        <ul>
 <?php $args = array( 
    'type'                     => 'post',
    'child_of'                 => '',
    'parent'                   => '',
    'orderby'                  => 'name',
    'order'                    => 'ASC',
    'hide_empty'               => 0,
    'hierarchical'             => 1,
    'exclude'                  => '',
    'include'                  => '',
    'number'                   => '',
    'taxonomy'                 => 'clients',
    'pad_counts'               => false ); ?>

<?php foreach (get_categoris($args) as $cat) : ?>
<li>
<a href=" <?php // WHAT GOES HERE?? ?>">
<img src="<?php echo z_taxonomy_image_url($cat->term_id); ?>"/></a></li>
<?php endforeach; ?>
  • 写回答

1条回答 默认 最新

  • doujie4787 2012-12-08 08:59
    关注

    GOT IT!!! WORKS!!

            <ul>
     <?php $args = array( 
        'type'                     => 'post',
        'child_of'                 => '',
        'parent'                   => '',
        'orderby'                  => 'name',
        'order'                    => 'ASC',
        'hide_empty'               => 0,
        'hierarchical'             => 1,
        'exclude'                  => '',
        'include'                  => '',
        'number'                   => '',
        'taxonomy'                 => 'clients',
        'pad_counts'               => false );
    
     $tax_menu_items = get_categories( $args );
     foreach ($tax_menu_items as $cat) : ?>
     <li>
     <a href=" <?php echo get_term_link($cat,$cat->taxonomy); ?> ">
        <img src="<?php echo z_taxonomy_image_url($cat->term_id); ?>" alt="<?php echo $cat->cat_name; ?>"/>
     </a>
     </li>
     <?php endforeach; ?>
    </ul>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 RPA正常跑,cmd输入cookies跑不出来
  • ¥15 求帮我调试一下freefem代码
  • ¥15 matlab代码解决,怎么运行
  • ¥15 R语言Rstudio突然无法启动
  • ¥15 关于#matlab#的问题:提取2个图像的变量作为另外一个图像像元的移动量,计算新的位置创建新的图像并提取第二个图像的变量到新的图像
  • ¥15 改算法,照着压缩包里边,参考其他代码封装的格式 写到main函数里
  • ¥15 用windows做服务的同志有吗
  • ¥60 求一个简单的网页(标签-安全|关键词-上传)
  • ¥35 lstm时间序列共享单车预测,loss值优化,参数优化算法
  • ¥15 Python中的request,如何使用ssr节点,通过代理requests网页。本人在泰国,需要用大陆ip才能玩网页游戏,合法合规。