dpl74687 2011-11-01 22:00
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PHP,MySQL查询总是返回1?

I know I have more than one result in the table, can anyone tell me what I am doing wrong?

<?php
$con = mysql_connect("x","y","z");
if (!$con)
{
die(mysql_error());
}
mysql_select_db("mydatabase", $con);
$query = ("SELECT COUNT(*) FROM usersonline WHERE datetime > NOW() - INTERVAL 5 MINUTE");
$result = mysql_query($query);
$num_rows = mysql_num_rows($result);
echo $num_rows;
?>
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2条回答 默认 最新

  • dtziv24262 2011-11-01 22:03
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    You're using the aggregate COUNT() function without a GROUP BY clause. It'll collapse the entire result set down and count the number of records, so all you'll ever get back is a 1-row-with-1-field result set.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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