preg_replace for Get Parameter - /index.php?color=blue&size=xl

Question

I have this url /index.php?color=blue&size=xl

to get rid of the get parameter, I use this code:

$done = preg_replace('/(.*)(\?|&)color=[^&]*(?(1)&|)?/i', "$1", $url);
echo $done;
"output: index.phpsize=xl"

Now I need to clean the "size" part too. Have tried with two lines of preg_replace, but it doesn´t work.

$done = preg_replace('/(.*)(\?|&)color=[^&]*(?(1)&|)?/i', "$1", $url);
echo $done;
$done2 = preg_replace('/(.*)(\?|&)size=[^&]*(?(1)&|)?/i', "$1", $done);

Edit: I really need a solution where I can clean the exact parameter "color" or "size".

Sometimes I will only delete one of them.

Edit2: Have this solution:

// Url is: index.php?color=black&size=xl&price=20

function removeqsvar($url, $varname) {
return preg_replace('/([?&])'.$varname.'=[^&]+(&|$)/','$1',$url);
}
$url = removeqsvar($url, color);
echo removeqsvar($url, price);

// will output: index.php?size=xl

Thank you all.

Answer 1

This will allow you to exactly specify which parameters to remove using the $remove array. It works by parsing the URL with parse_url(), then grabbing the query string and parsing it with parse_str().

From there, it's straightforward - Iterate over the parameters in the URL, if one of them is in the $remove array, then delete it from the $params array. By the end, if we have parameters to add to the URL, we add them back with http_build_query().

$url = '/index.php?color=blue&size=xl'; // Your input URL
$remove = array( 'color', 'size'); // Change this to remove what you want

$parts = parse_url( $url);
parse_str( $parts['query'], $params);

foreach( $params as $k => $v) {
    if( in_array( $k, $remove)) {
        unset( $params[$k]);
    }
}

$url = $parts['path'] . ((count( $params) > 0) ? '?' . http_build_query( $params) : '');
echo $url;