dongtanliefang8765 2017-11-13 02:16
浏览 67
已采纳

Golang在编组而不是编组时会忽略Json字段

Assume I have a password field in a User struct.

type User struct{
   UserName string `json:"username"`
   Password string `json:"-"`
}

My clients register their users by posting username and password together. So if I decode JSON to above struct, it ignores password. It's expected. But I wondered is there any way to ignore fields when only marshalling. I checked go official documentation page but couldn't find anything.

https://golang.org/pkg/encoding/json/

I can add an extra field into the struct but I need to know first is it possible to do that with JSON lib.

  • 写回答

3条回答 默认 最新

  • dsa80833 2017-11-13 08:21
    关注

    One common approach is to use a temporary type or variable, with same structure, but different json tags or even different structure:

    type User struct {
        UserName string `json:"username"`
        Password string `json:"password"`
    }
    
    func (usr User) MarshalJSON() ([]byte, error) {
        var tmp struct {
            UserName string `json:"username"`
        }
        tmp.UserName = usr.UserName
        return json.Marshal(&tmp)
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 java 的protected权限 ,问题在注释里
  • ¥15 这个是哪里有问题啊?