Go-将2字节数组转换为uint16值

Question

If I have a slice of bytes in Go, similar to this:

numBytes := []byte { 0xFF, 0x10 }

How would I convert it to it's uint16 value (0xFF10, 65296)?

Answer 1

you may use binary.BigEndian.Uint16(numBytes)
like this working sample code (with commented output):

package main

import (
    "encoding/binary"
    "fmt"
)

func main() {
    numBytes := []byte{0xFF, 0x10}
    u := binary.BigEndian.Uint16(numBytes)
    fmt.Printf("%#X %[1]v
", u) // 0XFF10 65296
}

and see inside binary.BigEndian.Uint16(b []byte):

func (bigEndian) Uint16(b []byte) uint16 {
    _ = b[1] // bounds check hint to compiler; see golang.org/issue/14808
    return uint16(b[1]) | uint16(b[0])<<8
}

I hope this helps.