在GoLang中将字节数组“ [] uint8”转换为float64

Question

I'm trying to convert a []uint8 byte array into a float64 in GoLang. I can't find a solution for this issue online. I've seen suggestions of converting to a string first and then to a float64 but this doesn't seem to work, it loses it's value and I end up with zeroes.

Example:

metric.Value, _ = strconv.ParseFloat(string(column.Value), 64)

And it doesn't work...

Answer 1

For example,

package main

import (
    "encoding/binary"
    "fmt"
    "math"
)

func Float64frombytes(bytes []byte) float64 {
    bits := binary.LittleEndian.Uint64(bytes)
    float := math.Float64frombits(bits)
    return float
}

func Float64bytes(float float64) []byte {
    bits := math.Float64bits(float)
    bytes := make([]byte, 8)
    binary.LittleEndian.PutUint64(bytes, bits)
    return bytes
}

func main() {
    bytes := Float64bytes(math.Pi)
    fmt.Println(bytes)
    float := Float64frombytes(bytes)
    fmt.Println(float)
}

Output:

[24 45 68 84 251 33 9 64]
3.141592653589793