dougou7008 2014-06-30 05:20
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Go中的Quicksort

I'm learning Go, and tried to implement a quicksort, however it doesn't return a complete list. To my understanding of Go it matches with a functioning Ruby implementation I wrote.

My code is:

func quickSort(data []string) []string {
  if len(data) > 1 {
    pivot := data[0]
    smaller := make([]string, 0, len(data))
    equal := make([]string, 0, len(data))
    larger := make([]string, 0, len(data))
    for i := 1; i < len(data); i++ {
      if data[i] > pivot {
        larger = append(larger, data[i])
      } else if data[i] < pivot {
        smaller = append(smaller, data[i])
      } else {
        equal = append(equal, data[i])
      }
    }
    return append(append(quickSort(smaller), equal...), quickSort(larger)...)
  } else {
    return data
  }
}

I am very puzzled as to what in this doesn't work.

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1条回答 默认 最新

  • dongxun6458 2014-06-30 06:35
    关注

    The bug you have is that you never append the pivot value to the returned slice. So for each recursive call, you will lose the pivot.

    Make the following change to the code and it will work:

    equal := make([]string, 1, len(data))
    equal[0] = pivot
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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