doutuobao4004 2018-11-15 16:39
浏览 101
已采纳

序列化结构以通过UDP发送

I'm trying to figure out how to serialize a struct and send it via UDP to my server. I managed to actually send the struct but upon receiving I do not have any values in it... Except when I statically add a number.

In the following code I am sending a UDP packet to port 8080 with a sequential number which are just the numbers from 0-9. I'm adding + 1 to it to show my point. What I expect is that on the receiving end I should receive in the message part 1-10. But the only thing I receive is the number 1 which means that the variable should be set to 0.

To verify if I actually send 0 I print the length of the buffer I receive and it is the correct length of what it should be. So I must be doing something wrong with the decoding.

send function:

func send_udp() {
    dst, _ := net.ResolveUDPAddr("udp", "localhost:8080")
    conn, _ := net.ListenPacket("udp", ":0")
    defer conn.Close()

    var buf bytes.Buffer
    encoder := gob.NewEncoder(&buf)
    for n := 0; n < 10; n++ {
        var msg int64 = int64(n) + 1
        packet := &Packet{[]int{5}, msg}
        encoder.Encode(packet)
        conn.WriteTo(buf.Bytes(), dst)
    }
}

The listen function:

func listen_udp() {
    dst, _ := net.ResolveUDPAddr("udp", "localhost:8080")
    conn, _ := net.ListenUDP("udp", dst)
    defer conn.Close()

    for {
        buf := make([]byte, 4096)
        n, _, _ := conn.ReadFromUDP(buf[:])
        fmt.Println(n)
        dec := gob.NewDecoder(bytes.NewReader(buf[:n]))
        p := Packet{}
        dec.Decode(&p)
        if len(p.Parts) != 0 {
            fmt.Printf("Received: %+v
", p)
        }
    }
}

the struct I'm trying to send:

type Packet struct {
    Parts   []int 
    Message int64 
}
  • 写回答

1条回答 默认 最新

  • dqxz96998 2018-11-15 20:20
    关注

    Implemented this on my local machine. Yes PLEASE check your errors, but lucky for you, nothing was returning any. Here is what I did to fix the problem. In send_udp initialize the Buffer and Encoder INSIDE the for loop.

    func send_udp() error {
        dst, err := net.ResolveUDPAddr("udp", "localhost:8080")
        if err != nil {
            return err
        }
        conn, err := net.ListenPacket("udp", ":0")
        if err != nil {
            return err
        }
        defer conn.Close()
    
        for n := 0; n < 10; n++ {
            // inside for loop
            var buf bytes.Buffer
            encoder := gob.NewEncoder(&buf)
    
            var msg int64 = int64(n) + 1
            packet := &Packet{[]int{5}, msg}
            err = encoder.Encode(packet)
            if err != nil {
                return err
            }
            _, err = conn.WriteTo(buf.Bytes(), dst)
            if err != nil {
                return err
            }
        }
        return nil
    }
    

    Note that declaring the Buffer outside the for loop, you were actually sending every previous Packet each time you added a new one, hence the increasing n values when you printed the return from ReadFromUDP in your listen_udp function, but it was only decoding the first one every time. So if you were meaning to send them all at once, you would have to loop over the Decoder in your listen_udp function.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 metadata提取的PDF元数据,如何转换为一个Excel
  • ¥15 关于arduino编程toCharArray()函数的使用
  • ¥100 vc++混合CEF采用CLR方式编译报错
  • ¥15 coze 的插件输入飞书多维表格 app_token 后一直显示错误,如何解决?
  • ¥15 vite+vue3+plyr播放本地public文件夹下视频无法加载
  • ¥15 c#逐行读取txt文本,但是每一行里面数据之间空格数量不同
  • ¥50 如何openEuler 22.03上安装配置drbd
  • ¥20 ING91680C BLE5.3 芯片怎么实现串口收发数据
  • ¥15 无线连接树莓派,无法执行update,如何解决?(相关搜索:软件下载)
  • ¥15 Windows11, backspace, enter, space键失灵