doulan9287
2019-02-21 19:01
浏览 893
已采纳

在Golang中将二进制值作为字符串转换为uint32

Hello i am trying to convert 00000000000000000000000000001011 to uint32 in golang using 

var v = "00000000000000000000000000001011"
fmt.Printf("%T
", v)
c := []byte(v)
u := binary.LittleEndian.Uint32(c)

However it is not working.

图片转代码服务由CSDN问答提供 功能建议

您好，我正在尝试使用 

 <将go000000中的00000000000000000000000000000000001011转换为uint32 代码> var v =“ 00000000000000000000000000001011” 
fmt.Printf（“％T 
”，v）
c：= [] byte（v）
u：= binary.LittleEndian.Uint32（c）
    
 
 
但是它不起作用。
  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 邀请回答

2条回答 默认 最新

  • dou47732 2019-02-21 19:16
    已采纳

    You can't use encoding/binary for this, as that is to serialize and deserialize the (memory) bytes of different values (e.g. numbers). What you have is the base 2 string representation of the number.

    To get its integer value you have to parse it. For that, use strconv.ParseUint():

    s := "00000000000000000000000000001011"
u, err := strconv.ParseUint(s, 2, 32)
if err != nil {
    panic(err)
}
fmt.Println(u)

    This outputs (try it on the Go Playground):

    11

    Note that strconv.ParseUint() returns a value of type uint64, so if you need uint32, you have to manually convert it, e.g.:

    u32 := uint32(u)

    There are more options for parsing numbers from strings, for an overview, check Convert string to integer type in Go?

    点赞 评论
  • dtsps00544 2019-02-21 19:18

    For example,

    package main

import (
    "fmt"
    "strconv"
)

func main() {
    s := "00000000000000000000000000001011"
    fmt.Println(s)
    u64, err := strconv.ParseUint(s, 2, 32)
    u32 := uint32(u64)
    if err == nil {
        fmt.Println(u32)
    }
}

    Playground: https://play.golang.org/p/yiicgWsb7B_M

    Output:

    00000000000000000000000000001011
11
    点赞 评论

报告相同问题？

提交

相关推荐 更多相似问题