doulan9287 2019-02-21 19:01
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在Golang中将二进制值作为字符串转换为uint32

Hello i am trying to convert 00000000000000000000000000001011 to uint32 in golang using

var v = "00000000000000000000000000001011"
fmt.Printf("%T
", v)
c := []byte(v)
u := binary.LittleEndian.Uint32(c)

However it is not working.

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  • dou47732 2019-02-21 19:16
    关注

    You can't use encoding/binary for this, as that is to serialize and deserialize the (memory) bytes of different values (e.g. numbers). What you have is the base 2 string representation of the number.

    To get its integer value you have to parse it. For that, use strconv.ParseUint():

    s := "00000000000000000000000000001011"
    u, err := strconv.ParseUint(s, 2, 32)
    if err != nil {
        panic(err)
    }
    fmt.Println(u)
    

    This outputs (try it on the Go Playground):

    11
    

    Note that strconv.ParseUint() returns a value of type uint64, so if you need uint32, you have to manually convert it, e.g.:

    u32 := uint32(u)
    

    There are more options for parsing numbers from strings, for an overview, check Convert string to integer type in Go?

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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