douzhajie7168 2014-10-03 00:58
浏览 13
已采纳

尝试从Go中的goroutines测试写入文件

Well, part of my code was working without a method approach, I'm trying to test append text to a file and reading from goroutines, but I'm stuck here trying to write it.

What is wrong? the file is created, but I can't append text to it, maybe something obvious, but seems I'm blind, maybe I'm failing understanding some language concepts...

package main

import (
    "bufio"
    "fmt"
    "os"
    "sync"
    "time"
)

var w sync.WaitGroup

type Buffer struct {
    F *os.File
}

func (buff *Buffer) Open(pathName string) (err error) {
    buff.F, err = os.OpenFile(pathName, os.O_APPEND|os.O_CREATE, 0666)
    if err != nil {
        return
    }
    fmt.Println("Open() ok")
    return nil
}
func (buff *Buffer) Close() (err error) {
    err = buff.F.Close()
    if err != nil {
        return
    }
    fmt.Println("Close() ok")
    return nil
}
func (buff *Buffer) Push(data string) (err error) {
    w := bufio.NewWriter(buff.F)
    _, err = fmt.Fprintf(w, "data=%s", data)
    if err != nil {
        return
    }
    w.Flush()
    fmt.Println("Push() ok")
    return nil
}
func checkErr(err error) {
    if err != nil {
        fmt.Println(err.Error())
    }
}
func worker() {
    var err error
    buffer := new(Buffer)
    err = buffer.Open("test")
    checkErr(err)
    err = buffer.Push("data
")
    checkErr(err)
    time.Sleep(5 * time.Second)
    err = buffer.Close()
    checkErr(err)
    w.Done()
}
func main() {
    w.Add(2)
    go worker()
    go worker()
    w.Wait()
}

Thanks

  • 写回答

1条回答 默认 最新

  • dotws86260 2014-10-03 01:15
    关注

    Open the file like this:

    buff.F, err = os.OpenFile(pathName, os.O_WRONLY|os.O_APPEND|os.O_CREATE, 0666)
    

    The write flag is required to write to the file.

    You missed the write error because the return from bufio Flush is ignored. Change Push to:

    func (buff *Buffer) Push(data string) (err error) {
        w := bufio.NewWriter(buff.F)
        _, err = fmt.Fprintf(w, "data=%s", data)
        if err != nil {
            return
        }
        err = w.Flush()
        if err != nil {
            return err
        }
        fmt.Println("Push() ok")
        return nil
    }
    

    To cleanly append data without intermixing with other pushes, the data must be written with a single call to the file Write method. Use a bytes.Buffer instead of a bufio.Writer to ensure a single call to the file Write method:

    func (buff *Buffer) Push(data string) (err error) {
        var b bytes.Buffer
        _, err = fmt.Fprintf(&b, "data=%s", data)
        if err != nil {
            return
        }
        _, err := buff.F.Write(b.Bytes())
        if err != nil {
            return err
        }
        fmt.Println("Push() ok")
        return nil
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 BP神经网络控制倒立摆
  • ¥20 要这个数学建模编程的代码 并且能完整允许出来结果 完整的过程和数据的结果
  • ¥15 html5+css和javascript有人可以帮吗?图片要怎么插入代码里面啊
  • ¥30 Unity接入微信SDK 无法开启摄像头
  • ¥20 有偿 写代码 要用特定的软件anaconda 里的jvpyter 用python3写
  • ¥20 cad图纸,chx-3六轴码垛机器人
  • ¥15 移动摄像头专网需要解vlan
  • ¥20 access多表提取相同字段数据并合并
  • ¥20 基于MSP430f5529的MPU6050驱动,求出欧拉角
  • ¥20 Java-Oj-桌布的计算