从golang中的字符或字符串之前的字符串grep子字符串的最佳方法

Question

I got net.Conn.RemoteAddr() as this:

192.168.16.96:64840

I only need IP address without port number

...
str := conn.RemoteAddr().String()
strSlice := strings.Split(str, ":")
ipAddress := strSlice[0]
...

Is there any simple way?

Answer 1

You can use net.SplitHostPort, like so

ip, _, err := net.SplitHostPort(conn.RemoteAddr().String())
if err != nil {
    fmt.Println(err)
    return
}
fmt.Println(ip)

Try it on the <kbd>Playground</kbd>

To answer OP's question in the comments above, net.SplitHostPort already deals with IPv6. Given the string

net.SplitHostPort("[2001:db8:85a3:0:0:8a2e:370]:7334")

Will work as intended.