2018-06-03 22:04

Golang-如何从矩阵中删除行？

So I have this 2D slice, for example:

``````s := [][]int{
{0, 1, 2, 3},
{4, 5, 6, 7},
{8, 9, 10, 11},
}

fmt.Println(s)

//Outputs: [[0 1 2 3] [4 5 6 7] [8 9 10 11]]
``````

How can I remove a full row from this 2D slice, so that the result would look like this if I decide to remove the middle row:

``````[[0 1 2 3] [8 9 10 11]]
``````
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2条回答

• dongre6404 3年前

The formula to delete row at index `i` is:

``````s = append(s[:i], s[i+1:])
``````

Here's a working example:

``````package main

import (
"fmt"
)

func main() {
s := [][]int{
{0, 1, 2, 3},
{4, 5, 6, 7}, // This will be removed.
{8, 9, 10, 11},
}

// Delete row at index 1 without modifying original slice by
// appending to a new slice.
s2 := append([][]int{}, append(s[:1], s[2:]...)...)
fmt.Println(s2)

// Delete row at index 1. Original slice is modified.
s = append(s[:1], s[2:]...)
fmt.Println(s)
}
``````

I recommend you to read Go Slice Tricks. Some of the tricks can be applied to multidimensional slices as well.

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• douan3182 3年前

You can try the following:

``````i := 1
s = append(s[:i],s[i+1:]...)
``````

You can try the working code in the Golang playground

Another alternative way is to use the following:

``````i := 1
s = s[:i+copy(s[i:], s[i+1:])]
``````

Golang Playground

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