Go中的Kinda“方法超载”？

Question

Assuming I got a type named State:

type State struct {
    // ... does not matter what is inside
}

along with a method defined on it:

func (s *State) prettyName() string {
    return "I am a state!"
}

Currently there is no way I can alter prettyName()'s behavior. I known that Go intentionally escapes OOP-like inheritance and methods overloading and this would probably never change, but still: what if I need prettyName() to behave differently depending upon whatever factor? The only solution I see is:

type State struct {
    _prettyName func() string
}
func (s *State) prettyName() string {
    return s._prettyName()
}

Is there a better Go-style way to achieve the same goal?

Answer 1

An interface should work here.

creating an interface like

type Stateful interface  {
    State() string
}

and a base state type

type BaseState struct{
}
func (s BaseState) State() string{
    return "Base state"
} 

you can imbed the BaseState struct

type MyStruct struct{
    BaseState
}

so that State Will return "Base state", but can also implement its own method.

func (s MyStruct) State() string{
    return "New State"
} 

and now State will return "New State"

https://play.golang.org/p/QOajW0O6gIz