将带有参数的函数传递给time.AfterFunc

Question

time.AfterFunc() accepts a duration and a function to be executed when that duration has expired. But the function cannot be a function that accepts parameters.

For example: The following function cannot be passed:

func Foo (b *Bar) {}

Although, it is possible to initialize a new function that calls the above one and then pass it:

f := func() {
    Foo(somebar)
}
timer := time.AfterFunc(1*time.Second, f)

Should this really be done this way?
Why does time.AfterFunc not accept any functions that accept parameters?
Do there exist other/better ways to do this?

Answer 1

Create a function from the argument, return it.

package main

import (
    "fmt"
    "time"
)

func foo(bar string) {
    fmt.Printf("in foo('%s')
", bar)
}

func newFunc(bar string) func() {
    fmt.Printf("creating func with '%s'
", bar)
    return func() {
        foo(bar)
    }
}

func main() {
    somebar := "Here we go!"
    f := newFunc(somebar)
    _ = time.AfterFunc(1*time.Second, f)

    time.Sleep(2 * time.Second)
}

https://play.golang.com/p/lWgeHvPLg9N