duanqiang9212
2018-04-03 09:09
浏览 532
已采纳

将带有参数的函数传递给time.AfterFunc

time.AfterFunc() accepts a duration and a function to be executed when that duration has expired. But the function cannot be a function that accepts parameters.

For example: The following function cannot be passed:

func Foo (b *Bar) {}

Although, it is possible to initialize a new function that calls the above one and then pass it:

f := func() {
    Foo(somebar)
}
timer := time.AfterFunc(1*time.Second, f)

Should this really be done this way?
Why does time.AfterFunc not accept any functions that accept parameters?
Do there exist other/better ways to do this?

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time.AfterFunc()接受一个持续时间和一个在该持续时间时要执行的函数 已过期。 但是该函数不能是接受参数的函数。

例如:无法传递以下函数:

  func Foo(b  * Bar){} 
   
 
 

尽管如此,可以初始化一个新函数来调用上面的函数,然后将其传递:

  f:= func(){
 Foo(somebar)
} 
timer:= time.AfterFunc(1 * time.Second,f)
   
  
 

真的要这样吗?
为什么time.AfterFunc不接受任何接受参数的函数?
是否存在其他/更好的方法? \ n

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1条回答 默认 最新

  • dongxiaoke2018 2018-04-03 09:21
    已采纳

    Create a function from the argument, return it.

    package main
    
    import (
        "fmt"
        "time"
    )
    
    func foo(bar string) {
        fmt.Printf("in foo('%s')
    ", bar)
    }
    
    func newFunc(bar string) func() {
        fmt.Printf("creating func with '%s'
    ", bar)
        return func() {
            foo(bar)
        }
    }
    
    func main() {
        somebar := "Here we go!"
        f := newFunc(somebar)
        _ = time.AfterFunc(1*time.Second, f)
    
        time.Sleep(2 * time.Second)
    }
    

    https://play.golang.com/p/lWgeHvPLg9N

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