Is it possible to execute code at a noon everyday? The program is handling user input the rest of its run time but needs to run a function at noon to output some text. What is the most effective way to do this?
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- duanbin198788 2016-07-15 03:08关注
So you need Interval Timer to run one function at noon everyday, you may use:
timer.AfterFunc()
ortime.Tick()
ortime.Sleep()
ortime.Ticker
first when program starts calculate time interval for start up time till first next noon and use some wait (e.g.
time.Sleep
or ...) then use24 * time.Hour
interval for the next interval.sample code using
time.Sleep
:package main import "fmt" import "time" func noonTask() { fmt.Println(time.Now()) fmt.Println("do some job.") } func initNoon() { t := time.Now() n := time.Date(t.Year(), t.Month(), t.Day(), 12, 0, 0, 0, t.Location()) d := n.Sub(t) if d < 0 { n = n.Add(24 * time.Hour) d = n.Sub(t) } for { time.Sleep(d) d = 24 * time.Hour noonTask() } } func main() { initNoon() }
and you may change main to this (or any thing you need):
func main() { go initNoon() // do normal task here: for { fmt.Println("do normal task here") time.Sleep(1 * time.Minute) } }
using
timer.AfterFunc
:package main import ( "fmt" "sync" "time" ) func noonTask() { fmt.Println(time.Now()) fmt.Println("do some job.") timer.AfterFunc(duration(), noonTask) } func main() { timer.AfterFunc(duration(), noonTask) wg.Add(1) // do normal task here wg.Wait() } func duration() time.Duration { t := time.Now() n := time.Date(t.Year(), t.Month(), t.Day(), 12, 0, 0, 0, t.Location()) if t.After(n) { n = n.Add(24 * time.Hour) } d := n.Sub(t) return d } var wg sync.WaitGroup
using
time.Ticker
:package main import ( "fmt" "sync" "time" ) var ticker *time.Ticker = nil func noonTask() { if ticker == nil { ticker = time.NewTicker(24 * time.Hour) } for { fmt.Println(time.Now()) fmt.Println("do some job.") <-ticker.C } } func main() { timer.AfterFunc(duration(), noonTask) wg.Add(1) // do normal task here wg.Wait() } func duration() time.Duration { t := time.Now() n := time.Date(t.Year(), t.Month(), t.Day(), 12, 0, 0, 0, t.Location()) if t.After(n) { n = n.Add(24 * time.Hour) } d := n.Sub(t) return d } var wg sync.WaitGroup
and see:
https://github.com/jasonlvhit/gocron
Golang - How to execute function at specific times
Golang: Implementing a cron / executing tasks at a specific time本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
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