dongwu1992 2014-08-02 04:55
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在Go中为map [string] interface {}创建方法

I have defined a Type

type UnknownMapString map[string]interface{}

I also have methods for them like so

func (m UnknownMapString) Foo() {
    fmt.Println("test!")
}

I get a panic when running:

interface conversion: interface is map[string]interface {}, not main.UnknownMapString

The map[string]interface{} is unmarshaled from JSON input.

Playground replicating it -> http://play.golang.org/p/kvw4dcZVNH

I thought that you could not have interface as a receiver of method so we needed to type assert (not convert?) to a Named Type and use that Named Type as the receiver of the method. Please let me know what I'm doing wrong. Thanks!

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  • duandi4815 2014-08-02 05:12
    关注
    val = val.(UnknownMapString)
    

    This is a type assertion, which supposes the named type UnknownMapString is identical to the unnamed type map[string]interface{}.
    And type identity tells us that:

    A named and an unnamed type are always different.

    But: you can assign a map[string]interface{} to a UnknownMapString because

    x is assignable to a variable of type T ("x is assignable to T") when:

    x's type V and T have identical underlying types and at least one of V or T is not a named type.

    This would work:

    var val2 UnknownMapString  = val.(map[string]interface{})
    val2.Foo()
    

    val2 is not an unnamed type, and both val2 and val.(map[string]interface{}) underlying types are identical.

    <kbd>play.golang.org</kbd>

    Output:

    test!
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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