doupai6875 2017-01-17 20:19
浏览 3
已采纳

无法修改数组内部的结构?

I'm just starting to learn golang and I have the following code:

https://play.golang.org/p/OBsf9MRLD8

package main

import (
    "encoding/json"
    "os"
)

type ResourceUsage struct {
    Type string
}
type Node struct {
    Resources []ResourceUsage
}

func main(){
    encoder := json.NewEncoder(os.Stdout)
    nodes := make([]Node, 2)
    nodes[0] = Node{}
    nodes[1] = Node{}

    for _,n := range nodes {
        n.Resources = append(n.Resources, ResourceUsage{Type: "test"})
    }
    encoder.Encode(nodes)
}

I was hoping it to print

[{"Resources":[{"Type:"test"}]},{"Resources":[{"Type:"test"}]}]

But instead I get:

[{"Resources":null},{"Resources":null}]

How can I accomplish the expected output?

  • 写回答

1条回答 默认 最新

  • douyi1963 2017-01-17 20:24
    关注

    Structs are copied in range loops. You need to access by index.

    for i := range nodes {
        nodes[i].Resources = append(nodes[i].Resources, ResourceUsage{Type: "test"})
    }
    

    You could also choose to use pointers, which would not copy data.

    nodes := make([]*Node, 2)
    nodes[0] = &Node{}
    nodes[1] = &Node{}
    

    @Kaedys points out, you can't take the address of the iterated value.

    for _, v := range nodes {
        &v // mistake
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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