doufu5521 2019-04-01 18:28
浏览 4
已采纳

使用属性解组xml

Having trouble getting xml to unmarshal so I can access xml attributes. Not sure what I'm doing wrong at this point. It complies, but the struct doesn't appear to contain any data.

import (
    "io/ioutil"
    "encoding/xml"
    "fmt"
)

contents of xml:

  <module id="Core" description="Core Module" tenantId="tenant1" major="3" minor="4" patch="0" build="0">
    <probePath path="bin" />
  </module>
</metadata>
type ModuleField struct {
    Id string `xml:"id,attr"`
    Description string `xml:"description,attr"`
    TenantId string `xml:"tenantId,attr"`
    Major string `xml:"major,attr"`
    Minor string `xml:"minor,attr"`
    Patch string `xml:"patch,attr"`
}

type Module struct {
    ModuleField ModuleField
    ProbePath string `xml:"probePath"`
}

type Metadata struct {
    XMLName xml.Name `xml:"metadata"`
    Module Module
}

// read xml file
    raw, _ := ioutil.ReadFile(XMLLoc)
    if err != nil {
        return
    }


    var XMLData Metadata 
    xml.Unmarshal(raw, &XMLData)

    // nothing is being printed
    fmt.Println(">",XMLData.Module.ModuleField.TenantId,"<")


  • 写回答

1条回答 默认 最新

  • dongranding3909 2019-04-01 18:46
    关注

    Letter case matters, so the element module will not be unmarshaled into a field called Module, you need to add the proper tag. Also you'll need to embed the ModuleField into Module so that its fields are promoted to Module and only then they will be unmarshaled. Or, alternatively, you can remove ModuleField and move all its fields into Module.

    https://play.golang.org/p/AvaEpcKY-oh

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 c程序不知道为什么得不到结果
  • ¥40 复杂的限制性的商函数处理
  • ¥15 程序不包含适用于入口点的静态Main方法
  • ¥15 素材场景中光线烘焙后灯光失效
  • ¥15 请教一下各位,为什么我这个没有实现模拟点击
  • ¥15 执行 virtuoso 命令后,界面没有,cadence 启动不起来
  • ¥50 comfyui下连接animatediff节点生成视频质量非常差的原因
  • ¥20 有关区间dp的问题求解
  • ¥15 多电路系统共用电源的串扰问题
  • ¥15 slam rangenet++配置