Windows XP SP3上的Accept（）超时设置

Question

I faced a critical issue while using go1.9.2 windows/386 on Windows XP SP3.

The Accept() blocks forever, even if I set a timeout using SetDeadline(), until the program exits.

I consider it critical because I can't stop listeners when I need to. Additionally, conn.Read() blocks forever as well, but I didn't include it to the example to make is simpler.

package main

import (
    "fmt"
    "net"
    "time"
)

func main() {

    listener, err := net.Listen("tcp", ":8888")
    if err != nil {
        fmt.Println(err.Error())
        return
    }

    tcplistener := listener.(*net.TCPListener)
    tcplistener.SetDeadline(time.Now().Add(time.Second * 2))

    fmt.Println("Listener started")

    go func() {

        defer func() {
            tcplistener.Close()
            fmt.Println("Listener closed")
        }()

        for {

            conn, err := listener.Accept()
            if err != nil {
                fmt.Println(err.Error())
                return
            }

            conn.Write([]byte("OK
"))
            conn.Close()

        }

    }()

    time.Sleep(time.Second * 10)

    fmt.Println("Exit")
}

Terminal output:

Listener started
Exit

In contrast, when I run this program on Windows 7 under VirtualBox (on the same Windows XP SP3), Accept() successfully unblocks after a timeout period.

Terminal output:

Listener started
accept tcp [::]:8888 i/o timeout
Listener closed
Exit

Answer 1

I've found a solution: reinstall Windows XP SP3.

I've tried to check how the app works on another installation of Windows XP SP3 and Windows XP SP2 and found that there were no issue.

Obviously, this means my XP works in a different way. Unfortunately, I have no ideas what is wrong.