在Linux和macOS上的Go中RFC3339的时间格式化结果不同

Question

I ran the go code following.

package main

import (
    "fmt"
    "strconv"
    "time"
)

func main() {
    i, err := strconv.ParseInt("1405544146", 10, 64)
    if err != nil {
        panic(err)
    }
    tm := time.Unix(i, 0).Format(time.RFC3339)
    fmt.Println(tm)
    fmt.Println(time.RFC3339)

}

Then the result on Linux is

2014-07-16T20:55:46Z
2006-01-02T15:04:05Z07:00

and on macOS is

2014-07-17T05:55:46+09:00
2006-01-02T15:04:05Z07:00

It's the same time but formatted results are different. Do you know the reason?

Answer 1

Don't jump to conclusions. Examine all the evidence. For instance, consider the local time zone.

Package time

import "time" 

func Unix

func Unix(sec int64, nsec int64) Time

Unix returns the local Time corresponding to the given Unix time, sec seconds and nsec nanoseconds since January 1, 1970 UTC.

---

For example,

package main

import (
    "fmt"
    "runtime"
    "strconv"
    "time"
)

func main() {
    i, err := strconv.ParseInt("1405544146", 10, 64)
    if err != nil {
        panic(err)
    }
    t := time.Unix(i, 0)
    fmt.Println(t)
    fmt.Println(t.Format(time.RFC3339))
    fmt.Println(time.RFC3339)
    fmt.Println(runtime.GOOS, runtime.GOARCH, runtime.Version())
}

Playground: https://play.golang.org/p/UH6o57YckiV

Output (Playground):

2014-07-16 20:55:46 +0000 UTC
2014-07-16T20:55:46Z
2006-01-02T15:04:05Z07:00
nacl amd64p32 go1.12

Output (Linux):

2014-07-16 16:55:46 -0400 EDT
2014-07-16T16:55:46-04:00
2006-01-02T15:04:05Z07:00
linux amd64 devel +5b68cb65d3 Thu Mar 28 23:49:52 2019 +0000

Different time zones (UTC versus EDT) so different formatted dates and times.

---

In your examples you have 2014-07-16T20:55:46Z and 2014-07-17T05:55:46+09:00, different time zones so different formatted dates and times.