douzhe2981 2016-01-27 11:52
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为什么这些Golang代码无法在多个时间中选择。

Why doesn't this Golang code to select among multiple time.After channels work?

See code below. The 'timeout' message is never issued. Why?

package main

import (
    "fmt"
    "time"
)

func main() {
    count := 0
    for {
        select {
        case <-time.After(1 * time.Second):
            count++
            fmt.Printf("tick %d
", count)
            if count >= 5 {
                fmt.Printf("ugh
")
                return
            }
        case <-time.After(3 * time.Second):
            fmt.Printf("timeout
")
            return
        }
    }
}

Run it on Playground: http://play.golang.org/p/1gku-CWVAh

Output:

tick 1
tick 2
tick 3
tick 4
tick 5
ugh
  • 写回答

2条回答 默认 最新

  • duanmiyang6201 2016-01-27 11:58
    关注

    Because time.After is a function, so on every iteration it returns a new channel. If you want this channel to be the same for all iterations, you should save it before the loop:

    timeout := time.After(3 * time.Second)
    for {
        select {
        //...
        case <-timeout:
            fmt.Printf("timeout
    ")
            return
        }
    }
    

    Playground: http://play.golang.org/p/muWLgTxpNf.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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