如何在golang上获取gocmq中断信号？ [关闭]

Question

** I use goczmq, but I don't catch system interrupt when run server on Windwos. Why?**

signal_channel := make(chan os.Signal)
signal.Notify(signal_channel)
go goczmq....
<-signal_channel

Answer 1

I did a quick example and seems to work as expected.
Having code in a.go :

package main

import (
"os"
"os/signal"
"time"
"fmt"
)

func main() {

fmt.Println( "Started...")
signal_channel := make(chan os.Signal)
signal.Notify(signal_channel)
go func() {
    // do whatever...
    time.Sleep(10 *time.Second)
}()
sig1 := <-signal_channel
fmt.Println( "

Got signal: ", sig1 )

fmt.Println( "Done.")

}

and

> go run a.go &
[1] 26515
Started...

>kill -HUP %1

Got signal:  hangup
Done. 

> go run a.go &
[1] 26768
> Started...

kill -USR1 %1

Got signal:  user defined signal 1

Also:

go run a.go  // + Press CTRL-Z
Started...
^Z
[1]+  Stopped                 go run a.go

Got signal:  stopped
Done.

and

> go run a.go // + Press CTRL-C 
Started...
^C

Got signal:  interrupt
Done.

If in your case it is not visible maybe it is consumed in gorutine. Like in:

package main

import (
    "os"
    "os/signal"
    "time"
    "fmt"
)

func main() {

    fmt.Println( "Started...")
    signal_channel := make(chan os.Signal)
    signal.Notify(signal_channel)
    go func() {
        // do whatever...
        sig2 := <-signal_channel
        fmt.Println( "gorutine sig2: ", sig2)
        time.Sleep(10 *time.Second)
    }()

    time.Sleep(10 *time.Second)
    sig1 := <-signal_channel
    fmt.Println( "

Got signal: ", sig1 )

    fmt.Println( "Done.")

}

which gets:

go run a.go Started...

^Cgorutine sig2:  interrupt