duanfen2349
2018-06-05 13:22
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如何解组不同数据类型的JSON数组?

Part of the JSON I'm trying to unmarshal has an array that can contain either strings or ints. How would I go about parsing this?

{
    "id": "abc",
    "values": [1,2,3]
},
{
    "id": "def",
    "values": ["elephant", "tomato", "arrow"]
},
{
    //etc...
}

I tried the following:

type Thing struct {
    ID      string   `json:"id"`
    Values  []string `json:"values,string,omitempty"`
}

Get the following error:

panic: json: cannot unmarshal array into Go struct field Thing.values of type string

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我要解组的JSON部分具有一个可以包含字符串或整数的数组。 我该如何解析?

  {
“ id”:“ abc”,
“ values”:[1,2,3] 
},  
 {
“ id”:“ def”,
“ values”:[“大象”,“番茄”,“箭头”] 
},
 {
 //等... 
}  
   
 
 

我尝试了以下操作:

  type Thing struct {
 ID string`json:“ id”  `
 Values [] string`json:“ values,string,omitempty”`
} 
   
 
 

出现以下错误: \ n

  panic:json:无法将数组解组到Go结构字段Thing.values类型为字符串
   
 
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1条回答 默认 最新

  • duanduan8439 2018-06-05 15:04
    已采纳

    You can set the type of the field Values to []interface{}, but you might have to use some type assertions.

    Here is a link to a playground where I use the data you provided: https://play.golang.org/p/ahePgggr8o1

    I will paste the code here anyways:

    package main
    
    import (
        "fmt"
        "encoding/json"
    )
    
    type Thing struct {
        ID      string   `json:"id"`
        Values  []interface{} `json:"values,omitempty"`
    }
    
    func print(values []interface{}) {
        for _, v := range values{
            switch value := v.(type){
            case string:
                fmt.Println("String", value)
            case int:
                fmt.Println("Integer", value)
            case float64:
                fmt.Println("Floats", value)
            default:
                fmt.Printf("I don't know about type %T!
    ", v)
            }
        }
    }
    
    func main() {
        var t1, t2 Thing
        data := []byte("{ \"id\": \"abc\", \"values\": [1,2,3]}")
        data2 := []byte("{ \"id\": \"def\", \"values\": [\"elephant\", \"tomato\", \"arrow\"]}")
        _ = json.Unmarshal(data, &t1)
        _ = json.Unmarshal(data2, &t2)
        print(t1.Values)
        print(t2.Values)
    }   
    
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