从FileInfo打开文件

Question

In golang, if I have an os.FileInfo, is there any way to open an *os.File from that by itself without the original path?

Let's say I had something like this:

package main

import (
    "os"
    "path/filepath"
    "strings"
)

var files []os.FileInfo

func walker(path string, info os.FileInfo, err error) error {
    if strings.HasSuffix(info.Name(), ".txt") {
        files = append(files, info)
    }
    return nil
}

func main() {
    err := filepath.Walk("/tmp/foo", walker)
    if err != nil {
        println("Error", err)
    } else {
        for _, f := range files {
            println(f.Name())
            // This is where we'd like to open the file
        }
    }
}

Is there a way to convert FileInfo to * File? The code I'm actually working with isn't based on filepath.Walk; but I do get an []os.FileInfo slice back. I still have the root directory, and the file name, but it seems like any further sub-tree information has gone by this stage.

Answer 1

No. The FileInfo interface simply does not expose the path and all provided methods in the os and ioutil packages accept the pathname as a string.