dszpyf4859 2015-11-06 14:37
浏览 29
已采纳

去json解组选项[重复]

This question already has an answer here:

Trying to find a simple solution to marshaling/unmashaling into the following struct

type Resource struct {
    Data []ResourceData `json:"data"`
}
type ResourceData struct {
    Id string  `json:"id"`
    Type string  `json:"type"`
    Attributes map[string]interface{} `json:"attributes"`
    Relationships map[string]Resource `json:"relationships"`
}
r := Resource{}
json.Unmarshal(body, &r)

this is great if:

body = `{"data":[{"id":"1","type":"blah"}]}`

However I also need it to respond to:

body = `{"data":{"id":"1","type":"blah"}}` //notice no slice

I could make a separate type

type ResourceSingle struct {
    Data ResourceData `json:"data"`
}

However, that would mean needing to duplicate all the functions I have attached to resource, which is possible. However, i would need to find out which type to unmarshal into before executing it, plus when it comes to the relationships part, each of those could contain data:[]{} or data{}, so that idea isn't going to work.

Alternatively I could use

map[string]*json.RawMessage
//or
type Resource struct {
    Data *json.RawMessage `json:"data"`
}

but still, when in json form how do I know if it is a slice or a node to supply the correct struct to unmarshal into?

My last resort is to umarshal into map[string]interface and use lots of reflect testing .. but this is very long winded.

Ideas?

Kind regards, jJ

</div>
  • 写回答

1条回答 默认 最新

  • dongzouche9108 2015-11-06 15:30
    关注

    There's a number of ways to structure it, but the simplest technique comes down to implementing a json.Unmarshaler, and inspecting the type of the data. You can minimally parse the json bytes, often just the first character, or you can try to unmarshal into each type and return the one that succeeds.

    We'll use the latter technique here, and insert the ResourceData into a slice regardless of the incoming data's format, so we can always operate on it in the same manner:

    type Resource struct {
        Data []ResourceData
    }
    
    func (r *Resource) UnmarshalJSON(b []byte) error {
        // this gives us a temporary location to unmarshal into
        m := struct {
            DataSlice struct {
                Data []ResourceData `json:"data"`
            }
            DataStruct struct {
                Data ResourceData `json:"data"`
            }
        }{}
    
        // try to unmarshal the data with a slice
        err := json.Unmarshal(b, &m.DataSlice)
        if err == nil {
            log.Println("got slice")
            r.Data = m.DataSlice.Data
            return nil
        } else if err, ok := err.(*json.UnmarshalTypeError); !ok {
            // something besides a type error occurred
            return err
        }
    
        // try to unmarshal the data with a struct
        err = json.Unmarshal(b, &m.DataStruct)
        if err != nil {
            return err
        }
        log.Println("got struct")
    
        r.Data = append(r.Data, m.DataStruct.Data)
        return nil
    }
    

    http://play.golang.org/p/YIPeYv4AfT

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥50 如何用脚本实现输入法的热键设置
  • ¥20 我想使用一些网络协议或者部分协议也行,主要想实现类似于traceroute的一定步长内的路由拓扑功能
  • ¥30 深度学习,前后端连接
  • ¥15 孟德尔随机化结果不一致
  • ¥15 apm2.8飞控罗盘bad health,加速度计校准失败
  • ¥15 求解O-S方程的特征值问题给出边界层布拉休斯平行流的中性曲线
  • ¥15 谁有desed数据集呀
  • ¥20 手写数字识别运行c仿真时,程序报错错误代码sim211-100
  • ¥15 关于#hadoop#的问题
  • ¥15 (标签-Python|关键词-socket)