不知道为什么这会在golang中陷入僵局？

Question

i'm new to Go not sure why this is deadlock ? i want to constantly be reading results from doSomething and storing it in the function read without using a for loop

func doSomething(c chan<- string){ // recursive function does something
    c <- result 
    return dosomething(c)  }

func reads(c <-chan string){
    results := ""   
    temp := <-c         
    results = results + "
" + temp      
    return results
}

func main(){     
    go reads(c)
    doSomething(c)
}

Answer 1

Main gorouting is trying to write multiple times to a channel in doSomething function. The read function is reading the channel only once. Therefore the write operation will wait until some other party reads from the channel. This will deadlock as the main goroutine is blocked.

If the blocking operations were not in main goroutine, the program would finish as the Go program ends whenever main goroutine ends. There would be no deadlock if main function could come to an end.