Java语言高分悬赏：输入三角形的3条边，判断三角形是不是直角三角形，怎么判断呢

直角三角形的基本特点是满足勾股定理，写个简单的判断就可以了。

public boolean isRightTriangle(int a, int b, int c)  {
    return (a > 0 && b > 0 && c > 0) && (a*a==b*b+c*c || b*b==a*a+c*c || c*c==a*a+b*b);
}

https://www.cnblogs.com/fyz666/p/6645966.html

public String shape(int a, int b, int c) {
String shape = "";
if (a * a == b * b + c * c && b * b == a * a + c * c
&& c * c == a * a + b * b) {
shape = "直角";
} else if (a * a > b * b + c * c && b * b > a * a + c * c
&& c * c > a * a + b * b) {
shape = "钝角";
} else if (a == b && b == c && a == c) {
shape = "等边";
} else {
shape = "锐角";
}