【高分悬赏】解析多层嵌套的json数据，取出json数据中的MP4文件

Question

通过okhttp网络请求方式获取到接口里参数path的MP4文件，麻烦写下完整的代码。我不知道怎么解析返回的数据

我的代码如下所示：
public class MainActivity extends AppCompatActivity {
final OkHttpClient client = new OkHttpClient();
// private final Gson gson = new Gson();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
getRequest();
}

private void getRequest() {

    final Request request = new Request.Builder()
            .get()
            .tag(this)
            .url("http://huaruanyun.cn:19001/get_play_list?devno=7C0CC5C2E3D69960")
            .build();

    new Thread(new Runnable() {
        @Override
        public void run() {
            Response response = null;
            try {
                response = client.newCall(request).execute();
                if (response.isSuccessful()) {

                    String result = response.body().string();

                    Log.i("qp", "打印GET响应的数据：" + result);
                } else {
                    throw new IOException("Unexpected code " + response);
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }).start();
}

}

Answer 1

String result = response.body().string();
JSONObject jsonObject = new JSONObject(result);
JSONArray jsonItems = jsonObject.getJSONArray("items");
for (int i = 0; i < jsonItems.length(); i++) {

JSONArray jsonData = jsonItems.getJSONObject(i).getJSONArray("tpl_data");
for (int e = 0; e < jsonData.length(); e++) {
    JSONArray jsonContent = jsonData.getJSONObject(e).getJSONArray("content");

    for (int n = 0; n < jsonContent.length(); n++) {
        path = jsonContent.getJSONObject(0).getString("path");


    }
}

}