大佬求解，如何向数组中存入时间呢

Question

各位大佬，如何向数组中存入时间呢，将时间作为一个变量存入数组中，并可以成功输出！求解

Answer 1

#include< iostream>
#include< time.h>
using namespace std;
int main(int argc, char const *argv[]){
time_t rawtime;
struct tm * arr[5];
time ( &rawtime );
arr[0] = localtime ( &rawtime );

int year,month,day,hour,min,sec;
year = 1900+arr[0]->tm_year;
month = 1+arr[0]->tm_mon;
day = arr[0]->tm_mday;
hour = arr[0]->tm_hour;
min = arr[0]->tm_min;
sec = arr[0]->tm_sec;
printf ( "当前时间:%4d-%02d-%02d %02d:%02d:%02d\n\n",year, month,day,hour,min,sec);
// printf ( "你需要的格式:%4d%02d%02d%02d%02d%02d\n\n",year, month,day,hour,min,sec);
return 0;

}