weixin_33691700 2017-11-18 18:48 采纳率: 0%
浏览 30

发送ajax数据到控制器

Without using MVC, I would have a page that has some jQuery which makes an ajax call to a specific php page, like:

$(document).ready(function(){
    $( "#login" ).on("click", function(e) {
        e.preventDefault();
        var form = $( "#loginForm" ).serialize();
        $.ajax({
            url: 'somePage.php',
            type: 'POST',
            dataType: 'json',
            data: form,
        })
        .done(function (data) {
            if(!data.success) {

                console.log(data.message);

            } else {

                console.log(data.message);
            }
        })
        .fail(function (jqXHR, textStatus, errorThrown) {
                console.log(textStatus + ': ' + errorThrown);
                console.warn(jqXHR.responseText);
            });
    });
});

somePage.php would look like:

if($_POST) {

    $response = array();
    $message = "";

if(empty($_POST['name'])) {

        $message .= "Name required";
    }

if($message) {

        $response['success'] = false;
        $response['message'] = $message;

    } else {

        // add data to database
        $response['success'] = true;
        $response['message'] = "Success";

    }

    echo json_encode($response);
}

I am new to MVC and OOP and am just wondering how I would change this because I would need to do the validation in the controller and then send the data to the model for database insert. The purpose of the ajax here is simply prevent page refresh when submitting the form and either display an error message if validation fails or show a success message if passes and then insert data into the database.

This is what my controller looks like at the moment for non ajax submission:

public function test() {

        if($_POST) {


            $data = [

                'email' => trim($_POST['email']),
                'email_err' => '' 
            ];

            if(empty($_POST['email'])) {

                $data['email_err'] = 'Email required';
            }

            if(empty($data['email_err'])) {

                //send data to model

            } else {

                $this->view('users/login', $data);
            }

        } else {

            $data = [

                'email' => '',
                'email_err' => ''
            ];

            $this->view('users/login', $data);
        }
    }

So, the question is basically how do I get the ajax response to the controller and the model? The error message would be displayed in the view.

  • 写回答

0条回答 默认 最新

    报告相同问题?

    悬赏问题

    • ¥15 delta降尺度计算的一些细节,有偿
    • ¥15 Arduino红外遥控代码有问题
    • ¥15 数值计算离散正交多项式
    • ¥30 数值计算均差系数编程
    • ¥15 redis-full-check比较 两个集群的数据出错
    • ¥15 Matlab编程问题
    • ¥15 训练的多模态特征融合模型准确度很低怎么办
    • ¥15 kylin启动报错log4j类冲突
    • ¥15 超声波模块测距控制点灯,灯的闪烁很不稳定,经过调试发现测的距离偏大
    • ¥15 import arcpy出现importing _arcgisscripting 找不到相关程序