简单的jQuery和PHP问题

Question

Does anyone know why this doesn't work? any help would be appreciated.

This is the HTML

Enter Code:<br/><input type="text" name="code" id="code"/><br/> 
<input type="button" id="confirm" value="Confirm" onClick="confirm()"/> 

This is the PHP (basically gets the value of the user input and if it's equal to the variable a echo sucess)

$code = $_POST["code"]; 
$a = 105678; 
if($code==$a){ 
  echo "sucess"; 
} else { 
  echo "nosucces"; 
} 

The JavaScript (simple ajax code to alert yay on PHP sucess or nay on no sucess)

function confirm () { 
  $.post(
    "confirm.php",
    {code:$(this).val() },
    function(data) { 
      if(data=='sucess') { 
        alert("yay"); 
      } else { 
        alert("nay");
      } 
    }
  ); 
}

basically on all occasions the ouput is nay on further debugging i tried an elseif statement on the javascript asking if data is equal to nosucces but it didn't even alert anything, meaning it's not getting the data from the php

Answer 1

Give brackets at end, so that it does understand that you are calling a function, also don't use confirm as function name, its a native JS function, use my_confirm instead.

onClick="my_confirm()"

Also $(this).val() won't work in your case use $('#code').val() instead.