package hdu;
import java.math.BigInteger;
import java.util.Scanner;
public class hdu1003 {
public static void main(String[] args){
Scanner cin=new Scanner(System.in);
int n=cin.nextInt();
for(int i=1;i<=n;i++){
BigInteger a=cin.nextBigInteger();
BigInteger b=cin.nextBigInteger();
BigInteger c=a.add(b);
System.out.println("Case"+" "+i+":");
System.out.println(a+" + "+b+" = "+c);
/*
*System.out.printf("Case %d:\n",i);
*System.out.printf("%d + %d = %d\n",a,b,c);
*这种提交结果是presentation error 为什么呢？
*我在加号和等号两边也加了一个空格的啊
*/
if(i<n) System.out.println();
}
cin.close();
}
}
题目是：
就是两个大数相加
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
