将代码添加完整，使输出如图所示

Question

注意！！！只是添加生成矩阵A和B，显示矩阵，矩阵相加这几个函数的代码和有？的地方，不能改变其他内容！
图片中有要求！！！

Answer 1

完整的示例程序如下：
#include

typedef struct
{
int pMat;/保存矩阵数据*/
int row;
int col;
}MAT,*pMAT;
/*字符串类型*/
typedef char * string;
/*生成矩阵A*/
void CreateMatA(pMAT a);
/*生成矩阵B*/
void CreateMatB(pMAT a);
/*显示矩阵*/
void ShowMat(string str,pMAT a);
/*矩阵相加*/
void MatAdd(pMAT a,pMAT b,pMAT c);

void main()
{
int m = 3;
int n = 4;
MAT A={0,m,n},B={0,m,n};
pMAT C = new MAT;

CreateMatA(&A);
CreateMatB(&B);
MatAdd(&A,&B,C);
ShowMat("A:",&A);
ShowMat("B:",&B);
ShowMat("C=A+B:",C);
delete A.pMat;/*释放内存*/
delete B.pMat;
delete C->pMat;
delete C;
printf("按任意键退出");
getch();/*按任意键退出*/

}
void CreateMatA(pMAT a)
{
int row,col;
int offset = 0;
int nV1,nV2;
a->pMat = new int[a->row * a->col];
for(row = 0;row < a->row;row++)
{
nV1 = (row + 1) * 10;
for (col = 0;col < a->col;col++)
{
nV2 = col * 2;
offset = row * a->col + col;
a->pMat[offset] = nV1 + nV2;
}
}
}
void CreateMatB(pMAT a)
{
int row,col;
int offset = 0;
int nV1,nV2;
a->pMat = new int[a->row * a->col];
for(row = 0;row < a->row;row++)
{
nV1 = (row + 1) * 10;
for (col = 0;col < a->col;col++)
{
nV2 = col * 1;
offset = row * a->col + col;
a->pMat[offset] = nV1 + nV2;
}
}
}
void ShowMat(string str,pMAT a)
{
int row,col;
int offset = 0;
printf("%s\n",str);
for(row = 0;row < a->row;row++)
{
for (col = 0;col < a->col;col++)
{
offset = row * a->col + col;
printf("%2d ",a->pMat[offset]);
}
printf("\n");
}
printf("\n");
}
void MatAdd(pMAT a,pMAT b,pMAT c)
{
int row,col;
int offset = 0;
c->row = a->row;
c->col = a->col;
c->pMat = new int[a->row * a->col];
for(row = 0;row < a->row;row++)
{
for (col = 0;col < a->col;col++)
{
offset = row * a->col + col;
c->pMat[offset] = a->pMat[offset] + b->pMat[offset];
}
}
}
运行结果如下：