微信获取共享地址出现错误，实在不知道怎么处理了

Question

 <script type="text/javascript">
 wx.config({
            debug: true,
            appId: '<?php echo $signPackage["appId"];?>',
            timestamp: '<?php echo $signPackage["timestamp"];?>',
            nonceStr: '<?php echo $signPackage["nonceStr"];?>',
            signature: '<?php echo $signPackage["signature"];?>',
            jsApiList: [
              // 所有要调用的 API 都要加到这个列表中
                'checkJsApi',
                'openAddress',
                'onMenuShareTimeline'
              ]
          });

wx.ready(function () {
   wx.checkJsApi({
                jsApiList: [
                    'openAddress',
                    'onMenuShareTimeline'
                ],
                success: function (res) {
                    alert(JSON.stringify(res));
                }
            });  

   wx.openAddress({
  success: function (res) {

alert('用户成功拉出地址2222');
},
cancel: function (errMsg) {
// 用户取消拉出地址
//alert(errMsg);
}});
})

为什么会显示openAddress：no，真是搞死人

Answer 1

http://laotu5i0.iteye.com/blog/2221977