okhttp-3.9.1 通过post形式提交数据，服务器返回参数未赋值

Question

1、 OKhttp通过键值对，进行post请求正常，代码如下：
// post提交键值对

         String url = "http://11-appaccess.myzmodo.com/zmd/user/usrlogin";

        OkHttpClient client = new OkHttpClient();

        RequestBody requestBody = new FormBody.Builder()
                .add("username", "[e-mail]")
                .add("password", "e10adc3949ba59abbe56e057f20f883e")
                .add("clienttype", "0")
                .add("language", "zh")
                .add("platform", "2")
                .build();
        Request request = new Request.Builder()
                .url(url)
                .post(requestBody)
                .build();

        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {

            }

            @Override
            public void onResponse(Call call, Response response) throws IOException {
                final String body = response.body().string();
                runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        Log.i("MainActivity", "body:" + body);
                    }
                });
            }
        });
2、**OKhttp通过json，进行post请求不正常**，代码如下：
//post提交json
        String url = "http://11-appaccess.myzmodo.com/zmd/user/usrlogin";
        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject.put("username", "[e-mail]");
            jsonObject.put("password", "e10adc3949ba59abbe56e057f20f883e");
            jsonObject.put("clienttype", "0");
            jsonObject.put("language", "zh");
            jsonObject.put("platform", "2");
        } catch (JSONException e) {
            e.printStackTrace();
        }
        String json = jsonObject.toString();
        Log.i("MainActivity", "json:" + json);

        MediaType JSON = MediaType.parse("application/json; charset=utf-8");
        OkHttpClient client = new OkHttpClient();

        RequestBody requestBody = RequestBody.create(JSON, json);
        Request request = new Request.Builder()
                .url(url)
                .post(requestBody)
                .build();
        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {

            }

            @Override
            public void onResponse(Call call, Response response) throws IOException {
                final String body = response.body().string();
                runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        Log.i("MainActivity", "body:" + body);
                    }
                });
            }
        });

Answer 1

String jsonStr = "{\"username\":\"lisi\",\"nickname\":\"李四\"}";//json数据
可能是你的JSON数据格式有问题