python中如何计算一个矩阵的点积

Question

我用i = np.dot(g,i)，计算得到图示矩阵，该怎么把他转换成一个值，就是ta的内积

Answer 1

如下

#!/usr/bin/python
# -*- coding: utf-8 -*-

import numpy as np
arr1 = np.array([0.025,0.02,0.03])
arr2 = np.array([0.02,0.015,0.04])
dotx = np.dot(arr1,arr2)
print(dotx)

更新：

#!/usr/bin/python
# -*- coding: utf-8 -*-

import numpy as np
h = np.array([[0,0,0,0,0,0,],[1/3,0,0,0,0,1/2],[1/3,1/2,0,1/2,0,0],[1/3,1/2,1,0,0,1/2],[0,0,0,0,0,0],[0,0,0,1/2,1,0]])
i = np.array([[0.3],[0.2],[0.1],[0.1],[0.1],[0.2]])
a = 0.85
j = np.array([[1,1,1,1,1,1],[1,1,1,1,1,1],[1,1,1,1,1,1],[1,1,1,1,1,1],[1,1,1,1,1,1],[1,1,1,1,1,1]])
g = a*h + (1-a) * (1/6) * j
 
n1 = np.squeeze(np.asarray(g))
n2 = np.squeeze(np.asarray(i))
f = np.dot(n1,n2)
print(np.dot(f,f))