问题如上：
输入 http://127.0.0.1/sqli/Less-1/?id=1'，但单引号被过滤，实际 sql 语句为 SELECT * FROM users WHERE id='1\'' LIMIT 0,1。
即 ' 被加了反斜杠。
请问如果绕过？
环境：
web使用php-study8.1.1.2 创建
mysql5.7.26
nginx1.15.11
php5.2.17nts
sql-labs第一题
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Less-1 **Error Based- String**</title>
</head>
<body bgcolor="#000000">
<div style=" margin-top:70px;color:#FFF; font-size:23px; text-align:center">Welcome <font color="#FF0000"> Dhakkan </font><br>
<font size="3" color="#FFFF00">
<?php
//including the Mysql connect parameters.
include("../sql-connections/sql-connect.php");
error_reporting(0);
// take the variables
if(isset($_GET['id']))
{
$id=$_GET['id'];
//logging the connection parameters to a file for analysis.
$fp=fopen('result.txt','a');
fwrite($fp,'ID:'.$id."\n");
fclose($fp);
// connectivity
$sql="SELECT * FROM users WHERE id='$id' LIMIT 0,1";
echo "你的 sql 语句是：".$sql."<br>";
$result=mysql_query($sql);
$row = mysql_fetch_array($result);
if($row)
{
echo "<font size='5' color= '#99FF00'>";
echo 'Your Login name:'. $row['username'];
echo "<br>";
echo 'Your Password:' .$row['password'];
echo "</font>";
}
else
{
echo '<font color= "#FFFF00">';
print_r(mysql_error());
echo "</font>";
}
}
else { echo "Please input the ID as parameter with numeric value";}
?>
</font> </div></br></br></br><center>
<img src="../images/Less-1.jpg" /></center>
</body>
</html>
