Python练习题:词频统计

Question

def getText():
    #获取文件
    text = open("Walden.txt","r").read()
    text = text.lower()
    for ch in '!"#$%&()*+,-./:;<=>?@[\\]^_‘{|}~' :
        text = text.replace(ch," ")
    return  text

txt = getText()
words = txt.split()
counts = {}               #定义空字典
for word in words:
    counts[word] = counts.get(word,0) + 1

items = list(counts.items())
#将列表按照count中键值从大到小的顺序进行排列
items.sort(key=lambda x:x[1],reverse=True)

#输出结果，前二十位最高频词汇
for i in range(10):
    word,count = items[i]
    print("#{0:<10}{1:>5}".format(word,counts))

词频统计代码如上，但是出现报错，请问这是什么原因啊？

Answer 1

打开文件语句中加入编码格式参数，改为text = open("Walden.txt","r"，encoding='utf-8‘).read()，试一下看看。另代码末尾打印语句中也有个小错误，是count而不是counts