求解答，这是怎么回事？

Question

#include<stdio.h>
#define N 15
void main()
{
	int a[N];
	int i,num,top,bott,mid,loca,flag=1,sign;
	char c;
	printf("enter data:\n");
	scanf("%d",&a[0]);
	i=1;
	while(i<N)
	{scanf("%d",&a[i]);
	if(a[i]>a[i-1])
		i++;
	else
		printf("enter again:\n");
	}
	printf("\n");
	for(i=0;i<N;i++)
		printf("%5d",a[i]);
	printf("\n");
	while(flag)
	{	printf("input number to look for:");
		scanf("%d",&num);
		sign=0;
		top=0;
		bott=N-1;
		if((num<a[0])||(num>a[N-1]))
			loca=-1;
		while((!sign)&&(top<=bott))
		{mid=(top+bott)/2;
		if(num==a[mid])
			{loca=mid;
			printf("has found %d ,its position is %d\n",num,loca+1);
			sign=1;
			}
		else if(num<a[mid])
			bott=mid-1;
		else
			top=mid+1;
		}
	if(!sign||loca==-1)
		printf("can't find %d.\n",num);
	printf("continue or not(Y/N)?\n");
	scanf("%c",&c);
	if(c=='N'||c=='n')
		flag=0;
	}
}

结果是：

enter data:
1 3 2
enter again:
4 5 6 8 12 23 34 44 45 56 57 58 68

    1    3    4    5    6    8   12   23   34   44   45   56   57   58   68
input number to look for:7
can't find 7.
continue or not(Y/N)?
input number to look for:12
has found 12 ,its position is 7
continue or not(Y/N)?
input number to look for:y
has found 12 ,its position is 7
continue or not(Y/N)?
input number to look for:n
has found 12 ,its position is 7
continue or not(Y/N)?
Press any key to continue

Answer 1

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