关于c++的flappy bird小游戏，出现了一个小问题

Question

在flappy bird游戏中 在添加多个障碍物时，后一个障碍物会变形。 (好像是前面的障碍物中的留的空造成的）

以下是完整代码：

```#include<iostream>
#include<cstdlib>
#include<conio.h>
#include<windows.h>
using namespace std;
int x=100;  
int y=20;
int birdx=x/8;
int birdy=y/4;
int speed=0;           
int bar1x=x/3;
int bar1y=rand()%(y/2);
int bar2x=x/2;
int bar2y=rand()%(y/2);

int count=0;


void notin();
void in();
void gotoxy(int x,int y)
     {
    HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
    COORD pos;
    pos.X=x;
    pos.Y =y;
    SetConsoleCursorPosition(handle,pos);
}
void HideCursor()
{
    CONSOLE_CURSOR_INFO cursor_info={1,0};
    SetConsoleCursorInfo(GetStdHandle(STD_OUTPUT_HANDLE),&cursor_info);
}
void map()
{
         gotoxy(0,0) ;
             HideCursor()   ;
             for(int i=1;i<y;++i)
             {
                 for(int j=1;j<x;++j)
                 {
                     if(j==birdx&&i==birdy)
                     {
                         cout<<"\b"<<"鸟"; 
                     }
                     else if((j==bar1x&&(i>=1&&i<=bar1y)||j==bar1x&&(i>=bar1y+5&&i<=y))||(j==bar2x&&(i>=1&&i<=bar2y)||j==bar2x&&(i>=bar2y+5&&i<=y)))
                     cout<<"HH";

                     else
                     cout<<" ";
                 }
                 cout<<endl;
             }

             cout<<"得分："<<count/6<<endl;

}
void control()
{
if(kbhit())
{
       string ss;
      ss=getch();

          if(ss==" ")
          {
            if(birdy>3)birdy-=3;
          }


}
}
void things()  
{
        if ((birdx==bar1x&& (birdy>=bar1y&&birdy<=bar1y+5))||(birdx==bar2x&& (birdy>=bar2y&&birdy<=bar2y+5)))
        count+=1;

      if(speed!=3)
      {
          speed++;   
      }
       if(birdy!=y&&speed==3)
   {
           birdy+=1;
           speed=0;
    }


     
     
          if(bar1x>0)
      {
          bar1x--;
      }
      
          if(bar2x>0)
      {
          bar2x--;
      }


      if(bar1x==0)
      {
           bar1x=x;
         bar1y= rand()%(y/2);
         while(bar1y==0)
         {
            bar1y= rand()%(y/2);
         }
             
      }
   
      if(bar2x==0)
      {
           bar2x=x;
         bar2y= rand()%(y/2);
         while(bar2y==0)
         {
            bar2y= rand()%(y/2);
         }

      }




}
int main()
{
    system("COLOR 17 ");
    while(bar1y==0)
{
      bar1y= rand()%(y/2);
}
      while(1)
{


            map();
            things();
            control(); 
            if((birdx==bar1x&&(((birdy>1&&birdy<bar1y))||(birdy >bar1y+5&&birdy<y)))||(birdx==bar2x&&(((birdy>1&&birdy<bar2y))||(birdy >bar2y+5&&birdy<y))))
{
         cout<<"YOU ARE FILLED!!"<<endl;
         break;
}    
}
}``

Answer 1

因为你其它行前面输出了两个HH，但这些问题行由于前面没有输出两个HH，只输出了一个空格，从而少输出了一个字符 你需要在输出HH的if处理中，记录一下该行是否已输出过HH，只要输出过，再次输出HH时，都需要先退一格 如果前面已经输出"鸟"，同样也需要先退一个再输出HH

    for(int i=1;i<y;++i)
    {
        int hh = 0;
        int bird = 0;
        for(int j=1;j<x;++j)
        {
            if(j==birdx&&i==birdy)
            {
                cout<<"鸟"; 
                bird = 1;
            }
            else if((j==bar1x&&(i>=1&&i<=bar1y)||j==bar1x&&(i>=bar1y+5&&i<=y))||(j==bar2x&&(i>=1&&i<=bar2y)||j==bar2x&&(i>=bar2y+5&&i<=y)))
            {
                if(hh == 1 || bird==1)
                {
                    cout<<"\b";
                }
                hh = 1;
                bird = 0;
                cout<<"HH";
            }
            else
                cout<<' ';
        }
        cout<<endl;
    }